Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
The separation between them is [tex]\frac{r}{\sqrt{20} }[/tex]
Concept :
If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.
Given,
Two point charges are brought closer together, increasing the force between them by a factor of 20.
Original force is
F = [tex]\frac{kq_{1} q_{2} }{r^{2} }[/tex] -------- ( 1 )
Here, [tex]q_{1} , q_{2}[/tex] are charges and r is the distance between them
New force F' = [tex]\frac{kq_{1q_{2} } }{r'^{2} }[/tex] ----------- (2 )
Divide ( 1 ) and ( 2 )
[tex]\frac{F'}{F}[/tex] = [tex]\frac{\frac{kq_{1}q_{2} }{r'^{2} } }{\frac{kq_{1}_{2} }{r^{2} } }[/tex]
20 = [tex]\frac{r^{2} }{r'^{2} }[/tex]
r' = [tex]\frac{r}{\sqrt{20} }[/tex]
Given that force between them are increasing and therefore distance between them decrease by [tex]\frac{r}{\sqrt{20} }[/tex]
Learn more about two point charges here : https://brainly.com/question/24206363
#SPJ4
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
