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A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. What strength of magnetic field will it have at its center?

Sagot :

A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. The strength of magnetic field at its center will be 2.5 * [tex]10^{-2}[/tex] H

Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.

A coil of wire which is designed to generate a strong magnetic field within the coil is called a solenoid. Wrapping the same wire many times around a cylinder creates a strong magnetic field when an electric current is passed through it. N denotes the number of turns the solenoid has.

Magnetic field at the center of the solenoid = mu0 * I * N / L

I = current in the solenoid

N = number of turns in the solenoid

L = length of the coil

B = 4π * [tex]10^{-7}[/tex] * 4 * 500 / 0.10

   = 251200 * [tex]10^{-7}[/tex] H

   = 2.5 * [tex]10^{-2}[/tex] H

To learn more about solenoids here

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