Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The mass (g) of a piece of magnesium wire that produces 41. 8 ml of hydrogen gas collected over water at 21. 0 °c and at a pressure of 752 torr is 0.041 gm.
Calculation,
According to ideal gas equation,
PV = nRT
Where, P is the pressure = 752 torr = 752 mmHg/760 mmHg/atm
P is the pressure in atm = 0.989atm
V is the volume = 41. 8 ml = 0.0418 L
R is the universal gas constant = 0.0821 Latm/mol K
T is the temperature = 21. 0 °C = 21. 0 + 273 = 294 K
n is the number of moles = ?
By putting value of P , V , T , and R in equation (i) we get,
0.989atm × 0.0418 L = n ×0.0821 Latm/mol K ×294 K
n = 0.989atm × 0.0418 L/0.0821 Latm/mol K×294 K = 0.00171 mol
Number of moles (n) = given mass/ molar mass = given mass/24.305
Mass = Number of moles×molar mass = 0.00171 mol×24.305 g/mol
Mass of the magnesium wire = 0.041 gm
learn more about hydrogen gas
https://brainly.com/question/12745309
#SPJ4
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
