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Sagot :
The munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
What are nonnegative real numbers?
- Non-negative real numbers are the set of positive real numbers that are bigger than 0 (zero).
- That is, the true values are either positive or negative.
- The collection will include numbers such as 0, 1, 2, 3, 4, 5, and so on.
To find the minimum value of 10x (3y/5):
Given - y = 3/(2x)
So, we want the bare minimum of,
- = 10x + 3/5 × 3/(2x)
- = 10x + 9/(10x)
Take the derivative to obtain:
- = 10 - 9/(10x^2)
When you set it to zero, you get:
- = 100x^2 - 9 = 0
- = (10x-3)(10x+3) = 0
- = x = ± 3/10
So, at x = 3/10, y = 5 and 10x + 3y/5 = 3 + 3 = 6.
Therefore, the munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
Know more about nonnegative real numbers here:
https://brainly.com/question/26606859
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