Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
What are nonnegative real numbers?
- Non-negative real numbers are the set of positive real numbers that are bigger than 0 (zero).
- That is, the true values are either positive or negative.
- The collection will include numbers such as 0, 1, 2, 3, 4, 5, and so on.
To find the minimum value of 10x (3y/5):
Given - y = 3/(2x)
So, we want the bare minimum of,
- = 10x + 3/5 × 3/(2x)
- = 10x + 9/(10x)
Take the derivative to obtain:
- = 10 - 9/(10x^2)
When you set it to zero, you get:
- = 100x^2 - 9 = 0
- = (10x-3)(10x+3) = 0
- = x = ± 3/10
So, at x = 3/10, y = 5 and 10x + 3y/5 = 3 + 3 = 6.
Therefore, the munimum value is, at x = 3/10, y = 5 and 10x+3y/5 = 6.
Know more about nonnegative real numbers here:
https://brainly.com/question/26606859
#SPJ4
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.