Orders of top-three finishers that are possible is given as follows:
[tex]n P_{r}=\frac{14 !}{11 !}=2184[/tex]
In a broad sense, a permutation of a set is the rearrangement of its elements inside an already ordered set, or the arrangement of its members into a sequence or linear order. The act or process of altering an ordered set's linear order is referred to as "permutation."
The number of possible permutations of x elements from a set of n elements is given by:
[tex]n P_{r}=\frac{n !}{(n-r) !}[/tex]
The order in which the cars finish is important, hence the permutation formula is used instead of the combination formula.
In this problem, 3 cars are taken from a set of 14, hence the number of different orders is given as follows:
Using the permutation formula, it is found that the number of different orders of top-three finishers that are possible is given as follows:
[tex]n P_{r}=\frac{14 !}{11 !}=2184[/tex]
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I understand that the question you are looking for is:
How many different orders of top-three finishers are possible? drag the tiles to the correct locations on the equation. not all tiles will be used.
