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Sagot :
Molar solubility of AgCl will be 0.59 × [tex]10^{-10}[/tex] M.
The amount of a chemical that can dissolve in one liter of a solution before reaching saturation is known as its molar solubility. This implies that the quantity of a substance it can disintegrate in a solution even before the solution becomes saturated with that particular substance is determined by its molar solubility.
A compound's molar solubility would be the measure of how many moles of such a compound must dissolve to produce one liter of saturated solution. The molar solubility unit will be mol L-1.
Calculation of molar solubility:
Given data:
M = 0.30 M
[tex]K_{sp}[/tex] = 1.77 × [tex]10^{-10}[/tex]
The reaction can be written as:
AgCl ⇔ [tex]Ag^{+} + Cl^{-}[/tex]
s s (s+0.30)
[tex]K_{sp}[/tex] = [[tex]Ag^{+}[/tex] ]+ [[tex]Cl^{-}[/tex]]
1.77 × [tex]10^{-10}[/tex] = s (0.30)
s = 1.77 × [tex]10^{-10}[/tex] / 0.3
s = 0.59 × [tex]10^{-10}[/tex] M
Therefore, molar solubility of AgCl will be 0.59 × [tex]10^{-10}[/tex] M.
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