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Sagot :
The molar mass of a gas if a flask with a volume of 3. 16 L contains 9. 33 grams of the gas at 32. 0°C and 1. 00 atm is 1.17g/mol
Calculation ,
In this question we have to fist find the number of moles of gas by using ideal gas equation and from the help of number of moles we can determine molar mass.
According to ideal gas equation which is also known as ideal law ,
PV = nRT ...( i )
where P is the pressure of the gas = 1 atm
V is the volume of the gas in the flask with volume = 3. 16 L
R is the universal gas constant = 0.082 atm L/K mol
T is the temperature = 32. 0°C = 32 + 273 = 305 K
n is the number of moles = ?
Putting the value of Pressure P , volume V , temperature T , number of moles n and universal gas constant R in the equation (i) we get ,
1 atm ×3. 16 L = n× 0.082 atm L/K mol ×305 K
n = 1 atm ×3. 16 L / 0.082 atm L/K mol × 305 K = 0.126 mole
number of mole of a gas = 0.126 mole = given mass/ molar mass
molar mass = number of moles × Given mass = 0.126 × 9. 33 = 1.17g/mol
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