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There are 0.138 gram copper could be electroplated on the cathode in an experiment where an average of 200 ma was passed through the cell for 35 minutes .
Calculation ,
Given ; Current passed through copper ( I ) = 200 mA = 200×[tex]10^{-3}[/tex] A
time in second = 35 minutes×60 = 2100 sec
Current ( I )= Q/t
Q =It = 200×[tex]10^{-3}[/tex] A × 2100 sec = 420 C
96500 C of charge = 1 mole
420 C of charge = 1 mole ×420 C/ 96500 C = 0.00435 mol
In , the valancy of Cu is +2 .
2 moles of electron are required for the decomposition of 1 mole of Cu on the cathode .
0.00435 mol of electron are required for the decomposition of Cu = 1mol × 0.00435 mol/2 = 0.002175 mol of Cu
Number of moles of Cu = given mass / molar mass
Mass of Cu = Number of moles of Cu × molar mass = 0.002175 ×63.546
Mass of Cu = 0.138 gram
Therefore , mass of copper is 0.138 gram
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