Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
If 2. 0 x 1023 argon {Ar) atoms strike 4. 0 [tex]cm^{2}[/tex] of wall per second at a 90° angle to the wall when moving with a speed of 45,000 [tex]cm^{-1}[/tex].The pressure will be 0.295 atm.
The force delivered perpendicularly to an object's surface per unit area across which that force would be dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure defines the pressure. The units was using to express pressure vary.
Calculation of force:
Force excerted by the Ar atoms, (F) = Change in momentum for one Ar atom 7 / unit time × number of atom
F = 2mv /1s × number of atoms.
Putting the given data in above equation.
F = 2 × 39.95 amu × 450 m/s/ 1s × 1.66 × [tex]10^{-27}[/tex] kg /amu × 2 × [tex]10^{23}[/tex] atom
F = 11.94 N
Now, pressure can be calculated by using the formula:
P = Force exerted /area
P = 11.94 N/ 4.0 [tex]cm^{2}[/tex] × [tex]cm^{2}[/tex]/ [tex]10^{-4} m^{2}[/tex]
P = 0.295 atm
Therefore, the pressure will be 0.295 atm.
To know more about pressure
https://brainly.com/question/12971272
#SPJ4
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
