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Sagot :
The molarity of an aqueous solution that is 6.75% glucose (C6H12O6) by mass is 3.86 M. The molality of the solution is 0.402m.
Now, an aqueous solution that is 6.75% glucose (C6H12O6) by mass means that 6.75g of glucose is dissolved in 93.25g of water resulting in a 100g solution.
Molar mass of C6H12O6 = 6x12 + 12x1 + 6x16
=72 + 12 + 96 = 180
No. of moles (n) of solute (C6H12O6) = Given mass / Molar mass
= 6.75 / 180 = 0.0375
Molarity (M) is defined as the number of moles of solute dissolved in one liter of solution.
Molarity = Moles of solute / Volume of solution in liter
= 0.0375 / [tex]\frac{1}{103}[/tex] = 3.86M
Molality (m) is defined as the number of moles of the solute per kilogram (kg) of the solvent and is expressed as:
Molality = Moles of solute / Mass of solvent in kg
= 0.0375 / [tex]\frac{93.25}{1000}[/tex] = 0.402m
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