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Sagot :
The correct option B.
The value of the zeros of function g is -6 and 7
What is Quadratic equation?
Any equation that can be rewritten in standard form as where x represents an unknown, a, b, and c represent known numbers, and where a 0 is true is a quadratic equation. As there is no ax2 term when a = 0, the equation is linear rather than quadratic.
According to the given information:
The factors are (x − 7) and (x + 6)
On simplifying the we get:
x²+ 6x -7x -42 = 0
x² - x - 42 = 0
The factorizing these equation we get.
So the zeros are -6 and 7 , so option b is correct.
[tex]x_{1,2}=\frac{-(-1) \pm \sqrt{(-1)^{2}-4 \cdot 1 \cdot(-42)}}{2 \cdot 1}[/tex]
[tex]$x_{1,2}=\frac{-(-1) \pm 13}{2 \cdot 1}\\[/tex]
[tex]x_1,_2[/tex] = ((1) ± 13)/2.1
[tex]x_1[/tex] = (1+13)/2.1
[tex]x_2[/tex] = (1 - 13)/2.1
[tex]X_1\\[/tex] = 7 , [tex]X_2[/tex] = -6
The Zeros of the function are: (7 , -6)
To know more about Quadratic equation visit:
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