ryanncaudillo07
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PLEASE HELP ME QUICK

In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA and BC
Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

Based on this construction, m∠ABP is ANSWER ° and m∠ABC is ANSWER°

PLEASE HELP ME QUICK In The Diagram Points D And E Are Marked By Drawing Arcs Of Equal Size Centered At B Such That The Arcs Intersect BA And BC Then Intersecti class=

Sagot :

mhanifa

Answer:

  • m∠ABP  is 32°,
  • m∠ABC is 64°.

Step-by-step explanation:

According to the construction we have:

  • BD = BE
  • PD = PE
  • BP - is common side of triangles BPD and BPE

It gives us:

  • ΔPBD ≅ ΔPBE

Then, corresponding angles of congruent triangles are congruent:

  • ∠DBP ≅ ∠EBP

So,

  • ∠ABP ≅ ∠CBP ⇒ m∠ABP = 32°

Then,

  • m∠ABC = m∠ABP + m∠CBP = 32° + 32° = 64°  
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