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PLEASE HELP 100 POINTS!
Pyramid A is a square pyramid with a base side length of 14 inches and a height of 6 inches. Pyramid B has a volume of 3,136 cubic inches. How many times bigger is the volume of pyramid B than pyramid A? Give your answer as a percentage. Provide an explanation and proof for your answer to receive full credit.


PLEASE HELP 100 POINTS Pyramid A Is A Square Pyramid With A Base Side Length Of 14 Inches And A Height Of 6 Inches Pyramid B Has A Volume Of 3136 Cubic Inches H class=

Sagot :

Answer:

800%

Step-by-step explanation:

Volume of a square based pyramid

[tex]\sf V=\dfrac{1}{3}a^2h[/tex]

where:

  • a = base side length
  • h = height

Given values for Pyramid A:

  • a = 14 inches
  • h = 6 inches

Substitute the given values into the formula to find the volume of Pyramid A:

[tex]\begin{aligned}\textsf{Volume of Pyramid A} & = \sf \dfrac{1}{3}(14)^2(6)\\\\& = \sf \dfrac{1176}{3}\\\\& = \sf 392\:\: in^3 \end{aligned}[/tex]

Given:

  • Volume of Pyramid B = 3136 in³

To find how many times bigger Pyramid B is than Pyramid A, divide the volume of Pyramid B by the volume of Pyramid A:

[tex]\implies \sf \dfrac{3136}{392}=8[/tex]

Therefore, the volume of Pyramid B is 8 times bigger than the volume of Pyramid A.

8 as a percentage is 800%, since 800/100 = 8.

Therefore, the volume of Pyramid B is 800% the volume of Pyramid A.

To verify this, find 800% of the volume of Pyramid A:

⇒ 800% of 392

= 800/100 × 392

= 8 × 392

= 3136

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