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Sagot :
The molarity of the NaOH is 0.238 M when 1. 477 g sample of KHP required 30. 27 ml of NaOH solution to reach endpoint.
Calculation ,
Mass of KHP = 1. 477 g
Number of moles of KHP = given mass / molar mass of KHP
Number of moles of KHP = 1. 477 g × 1 mol / 204.23 g KHP = 0.007 mol
Since , one mole KHP requires one mole of NaOH .
Number of moles of NaOH required by 0.007 mol of KHP = 0.007 mol
Molarity of NaOH = number of moles / volume in lit = 0.007mol/0.03027ml = 0.238 M
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