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Sagot :
The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V
Calculation ,
Formula used :
[tex]E_{cell}[/tex] = [tex]E_{cell}[/tex] ° - 0.059/n ㏒[tex]H_{2}[/tex]/ [tex][H^{+}]^{2}[/tex]
As we know that ,
[[tex]H^{+}[/tex]] = 0. 84 M
[tex]P_{H_{2}[/tex] = 2. 2 atm
Temperature ( T ) = 298 K
From reaction at electrode number of electrons involve ( n ) = 1
Standard electrode potential of standard hydrogen electrode [tex]E_{cell}[/tex] ° = 0
Putting the value of all data in equation ( i ) , we get
[tex]E_{cell}[/tex] = 0 - 0.059/1 ㏒2. 2 / [tex](0. 84)^{2}[/tex] = - 0.059 ㏒3.14 = - 0.059×0.497
[tex]E_{cell}[/tex] = - 0.029 V
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