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Mass m moves to the right with speed =v along a frictionless horizontal surface and crashes into an equal mass m initially at rest. upon colliding, the two masses stick together and move with speed v to the right. notice that v and v denote different speeds. after the collision the magnitude of the momentum of the system is:

Sagot :

After the collision the magnitude of the momentum of the system is Mv

Given:

mass of 1st object = M

speed of 1st object = v

mass of 2nd object = M

speed of 2nd object = 0

To Find:

magnitude of the momentum after collision

Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.

Applying conservation of linear momentum

Mv + M(0) = 2MV

Mv = 2MV

V = v/2

So, after collision momentum is

p = 2MV = 2xMxv/2 = Mv

So, after collision momentum is Mv

Learn more about Momentum here:

https://brainly.com/question/1042017

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