Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
standard form of the given equation are
-f(*) = (x + 2)(x - 6) = x² - 4x - 12
f(x) = (x - 4)(x + 3) = x² - x - 12
f(x) = (x - 12)(x + 1) = x² - 11x - 12
f(x) = (x -3)(x + 4) = x² + x - 12
What is quadratic function?
A polynomial function with one or more variables in which the second-degree term is the highest degree is known as a quadratic function, quadratic polynomial, polynomial of degree 2, or simply a quadratic, in algebra.
What is standard form of a quadratic function?
As long as an is not equal to zero, the quadratic function f(x) = a(x - h)2 + k is considered to be in standard form. The graph starts out in either an upward or a downward direction depending on the value of a. The point at the vertex of the symmetry is represented by the vertical line x = h. (h,k).
According to the given information:
The standard form list.
1 . (x + 2)(x - 6)
= x² - 6x + 2x - 12
= x² - 4x -12
2. (x - 4)(x + 3)
= x² + 3x - 4x - 12
= x² - x - 12
3. (x - 12)(x + 1)
= x² + 1x - 12x - 12
= x² - 11x - 12
4. (x -3)(x + 4)
= x² + 4x - 3x - 12
= x² + x - 12
So the equivalent standard form of the give values are :
-f(*) = (x + 2)(x - 6) = x² - 4x - 12
f(x) = (x - 4)(x + 3) = x² - x - 12
f(x) = (x - 12)(x + 1) = x² - 11x - 12
f(x) = (x -3)(x + 4) = x² + x - 12
To know more about quadratic function visit:
https://brainly.com/question/17177510
#SPJ4
I understand that the question you are looking for is:
Match each quadratic function given in factored form
with its equivalent standard form listed on the left.
f(x) = (x + 2)(x – 6)
f(x) = (x – 4)(x+3)
f(x) = (x – 12)(x+1)
f(x) = (x – 3)(x +4)
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
