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Question 1: The population of Ohio's three largest cities are: Cleveland, 479,459; Columbus, 715,230; and Cincinnati, 367,000. The average population of Ohio's three largest cities is:
a. 520,563
b. 620,563
c. 502,563
d. 602,563

Q2: Mr. Gorski bases each student's grade on 4 tests. On the first 3 tests, Horace scored 84, 93, and 88. What must he score on the final test to make his average 90?
a. 85
b. 88
c. 92
d. 95


Sagot :

Hello there! The answer to question 1:

A. 520,563

The answer to question 2:

D. 95

To solve question one, we need to find the average of these three numbers. To do so, we add all three first:

479,459 + 715,230 + 367,000 = 1,561,689

Then, after adding, we can divide our result by three because that is how many numbers were used.

1,561,689 divided by 3 = 520,563

Therefore, the average population of Ohio’s three largest cities is 520,563.

To find the answer to question two, we can start by adding the three numbers we have:

84 + 93 + 88 = 265

Because Horace had two tests where he scored in the eighties, we know that in order to average at least a 90, Horace will need to score either a 92 or a 95. When calculating, we will find that if Horace scores a 92, he will be at an average of 89.25. That means that our only reasonable answer is 95 because we can calculate that:

84 + 93 + 88 + 95 = 360

360 divided by 4 equals 90.

Therefore, scoring a 95 on Horace’s final test will put him right on the dot for an average of 90.

Your final answer is D, or 95. Horace will need to score a 95 on his final test to average out to a 90. If you need any extra help, let me know and I will gladly assist you.