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1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm. Half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The cylinder changes volume to maintain constant pressure. What is the volume in the final system?

10 Mole Of A Gas Is Enclosed In A 123 Liter Cylinder With A Moveable Piston At 300 K And 20 Atm Half Of The Gas Is Removed Leaving 050 Mole In The Cylinder And class=

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samueladesida43

The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

How to calculate volume?

The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;

P1V1/T1 = P2V2/T2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • T1 = initial temperature
  • T2 = final temperature
  • V1 = initial volume
  • V2 = final volume

According to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.

However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:

2 × 12.3/300 = 2 × V2/900

0.082 = 2V2/900

73.8 = 2V2

V2 = 73.8 ÷ 2

V2 = 36.9L

Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.

Learn more about volume at: https://brainly.com/question/12357202

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