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Sagot :
The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.
c = 3 * [tex]10^{8}[/tex] m/s
∈ = 8.85 * [tex]10^{- 12}[/tex] [tex]C^{2}[/tex] / N/ [tex]m^{2}[/tex]
E = 0. 060 v/m
I = P / 4π[tex]r^{2}[/tex]
Also , I = c ∈ [tex]E^{2}[/tex] /2
[tex]r^{2}[/tex] = P / 4π I equation 1
substituting the value of I in equation 1
[tex]r^{2}[/tex] = 2 P / 4π (c ∈ [tex]E^{2}[/tex] )
[tex]r^{2}[/tex] = 2 * 27 * [tex]10^{-3}[/tex] / 4 * 3.14 * 3 * [tex]10^{8}[/tex] * 8.85 * [tex]10^{- 12}[/tex] * [tex](0.06)^{2}[/tex]
r = 21.21 m
To learn more about Electromagnetic waves here
https://brainly.com/question/12392559
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