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The value of the rate constant at 302°c is 2. 45 × 10-4 l/mol s and at 508°c the rate constant is 0. 0965 l/mol s. the value of r is 8. 3145 j/k mol. Calculate the activation energy for this reaction

Sagot :

The activation energy for this reaction is - 55.5 kJ/mol

Calculation,

Given data,

First temperature [tex]T_{1}[/tex] =  302°C = 302+273 = 575 K

Second temperature [tex]T_{2}[/tex] =  508°C =  508+273 = 781 K

rate constant at  302°C = 2. 45 × [tex]10^{-4}[/tex] lit/mol s

rate constant at 508°C =  0. 0965 lit/mol s.

Value of universal gas constant = 8.3145 J/k mol.

Apply Arrhenius equation,

㏒[tex]K_{1} /K_{2}[/tex] = [tex]E_{a}/2.203R[/tex] [1/ 575 K - 1/781 K]

㏒2. 45×[tex]10^{-4}[/tex] lit/mol s/0.0965 lit/mol s = [tex]E_{a}[/tex] /2.303×8.3145 J/k mol[781-575/575K×781 K]

[tex]E_{a}[/tex] = - 55.5 kJ/mol

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