Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
A charge q = -10 µc experiences an electrostatic force of 35 mn to the left.
The magnitude of electric field will be = 35 * [tex]10^{2}[/tex] N/C
Direction of the electric field will be from left to right
The force exerted by a charged body on another charged or uncharged body is called electrostatic force. This force is known as non-contact force because these forces comes into play even when the bodies are not in contact with each other.
Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.
given
q ( charge ) = -10 µc
Electrostatic force = 35 mN
Electric field = Force on charge / charge
= 35 * [tex]10^{-3}[/tex] / (-10 * [tex]10^{-6}[/tex])
= - 35 * [tex]10^{2}[/tex] N/C
To learn more about Electric field here
https://brainly.com/question/15800304
#SPJ4
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
