Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
A charge q = -10 µc experiences an electrostatic force of 35 mn to the left.
The magnitude of electric field will be = 35 * [tex]10^{2}[/tex] N/C
Direction of the electric field will be from left to right
The force exerted by a charged body on another charged or uncharged body is called electrostatic force. This force is known as non-contact force because these forces comes into play even when the bodies are not in contact with each other.
Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.
given
q ( charge ) = -10 µc
Electrostatic force = 35 mN
Electric field = Force on charge / charge
= 35 * [tex]10^{-3}[/tex] / (-10 * [tex]10^{-6}[/tex])
= - 35 * [tex]10^{2}[/tex] N/C
To learn more about Electric field here
https://brainly.com/question/15800304
#SPJ4
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
