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Sagot :
A charge q = -10 µc experiences an electrostatic force of 35 mn to the left.
The magnitude of electric field will be = 35 * [tex]10^{2}[/tex] N/C
Direction of the electric field will be from left to right
The force exerted by a charged body on another charged or uncharged body is called electrostatic force. This force is known as non-contact force because these forces comes into play even when the bodies are not in contact with each other.
Electric field, an electric property associated with each point in space when charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.
given
q ( charge ) = -10 µc
Electrostatic force = 35 mN
Electric field = Force on charge / charge
= 35 * [tex]10^{-3}[/tex] / (-10 * [tex]10^{-6}[/tex])
= - 35 * [tex]10^{2}[/tex] N/C
To learn more about Electric field here
https://brainly.com/question/15800304
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