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Sagot :
The new concentrations of [tex]HClO[/tex] and [tex]NaClO[/tex] are 0.25M and 19M
Calculation of number of moles of each component,
Molarity of [tex]HClO[/tex] = number of moles/volume in lit = 0. 500 M
Number of moles = molarity of [tex]HClO[/tex]× volume in lit = 0. 500 M× 0.025 L
Number of moles of [tex]HClO[/tex] = 0.0125 mole
Molarity of [tex]NaClO[/tex] = number of moles/volume in lit = 0. 38 M
Number of moles = molarity of [tex]NaClO[/tex] × volume in lit = 0. 38 M× 0.025 L
Number of moles of [tex]NaClO[/tex] = 0.95 mole
Calculation of new concentration at volume 50 ml ( 0.05L)
Molarity of [tex]HClO[/tex] = number of moles/volume in lit = 0.0125 mole/0.05L
Molarity of [tex]HClO[/tex] = 0.25M
Molarity of [tex]NaClO[/tex] = number of moles/volume in lit = 0.95mole/0.05L
Molarity of [tex]NaClO[/tex] = 19 M
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