Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

. Barium has a work function of 2.48eV. What is the maximum kinetic energy if the metal is illuminated by UV light of wavelength 365nm?​

Sagot :

The maximum kinetic energy is 0.91 eV

What is Work Function of a Metal ?

A Work Function of a Metal is the minimum energy required to liberate an electron from a metal surface. From the formula;

hF = hf + E

  • hF = energy for liberation or illumination
  • hf = work function = 2.8 eV
  • E = kinetic energy

Given that a Barium has a work function of 2.48eV. What is the maximum kinetic energy ?

Convert eV to Joule by multiplying by 1.6 x [tex]10^{-19}[/tex]

hf = 2.48 x 1.6 x [tex]10^{-19}[/tex]

hf = 3.968 x [tex]10^{-19}[/tex] J

If the metal is illuminated by UV light of wavelength 365nm,

E = hF = hc/λ

Where

  • C = speed of light = 3 x [tex]10^{8}[/tex] m/s
  • h = Planck constant = 6.6 x [tex]10^{-34}[/tex] Js
  • λ = wavelength = 365 x [tex]10^{-9}[/tex] m

Substitute all the parameters

hF = (6.6 x [tex]10^{-34}[/tex] x  3 x [tex]10^{8}[/tex]) / 365 x [tex]10^{-9}[/tex]

hF = 1.98 x [tex]10^{-25}[/tex] /  365 x [tex]10^{-9}[/tex]

hF = 5.42 x [tex]10^{-19}[/tex] Joule

The maximum kinetic energy will be

hF = hf + E

Make E the subject of formula

E = hF - hf

E = 5.42 x [tex]10^{-19}[/tex] - 3.968 x [tex]10^{-19}[/tex]

E = 1.452 x [tex]10^{-19}[/tex] J

Convert Joule back to eV by dividing by 1.6 x [tex]10^{-19}[/tex]

E = 1.452 x [tex]10^{-19}[/tex] / 1.6 x [tex]10^{-19}[/tex]

E = 0.9075 eV

Therefore, the maximum kinetic energy is 0.91 eV approximately

Learn more about Work Function here: https://brainly.com/question/14144692

#SPJ1