Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What mass (g) of calcium chloride, CaCl2, is needed to prepare 2.451 L of a 1.56 M solution

Sagot :

CrystalQueen

Answer:

424 grams CaCl₂

Explanation:

To find the mass of CaCl₂, you need to (1) calculate the moles (using the molarity ratio) and then (2) convert moles to grams (using the molar mass). The final answer should have 3 sig figs to match the given value with the least amount of sig figs.

(Step 1)

Molarity (M) = moles / volume (L)

1.56 M = moles / 2.451 L

3.82 = moles

(Step 2)

Molar Mass (CaCl₂): 40.078 g/mol + 2(35.453 g/mol)

Molar Mass (CaCl₂): 110.984 g/mol

3.82 moles CaCl₂           110.984 g
----------------------------  x  -------------------  =  424 grams CaCl₂
                                          1 mole

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.