Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

*please refer to photo attached* The figure below shows a small, charged sphere, with a charge of q = +44.0 nC, that moves a distance of d = 0.189 m from point A to point B in the presence of a uniform electric field E of magnitude 300 N/C, pointing right.


What is the magnitude (in N) and direction of the electric force on the sphere?
magnitude_______N
Direction?
- toward the right
- toward the left
- the magnitude is zero


(b) What is the work (in J) done on the sphere by the electric force as it moves from A to B?
__________J


(c) What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.)
PEB − PEA = ______J


(d) What is the potential difference (in V) between A and B?
VB − VA = ________V


Please Refer To Photo Attached The Figure Below Shows A Small Charged Sphere With A Charge Of Q 440 NC That Moves A Distance Of D 0189 M From Point A To Point B class=

Sagot :

(a) The magnitude of the force is 1.32 x 10⁻⁵ N and direction of the electric force on the sphere towards the right.

(b) The work done on the sphere by the electric force as it moves from A to B is 2.5 x 10⁻⁶ J.

(c) The change of the electric potential energy as the sphere moves from A to B is 2.5 x 10⁻⁶ J.

(d) The potential difference between A and B is 56.7 V.

Electric force on the sphere

The electric force on the sphere is calculated as follows;

F = Eq

where;

  • E is electric field
  • q is the charge

F = 300 x (44 x 10⁻⁹)

F = 1.32 x 10⁻⁵ N

The direction of the force is towards the right.

Work done on the sphere

W = Fd

W = 1.32 x 10⁻⁵ N  x 0.189 m

W = 2.5 x 10⁻⁶ J

Change of the electric potential energy

The change in the electric potential energy (in J) as the sphere moves from A to B is equal to work done in moving the charge = 2.5 x 10⁻⁶ J.

Potential difference between A and B

VB − VA =  Ed

VB − VA =  300 N/C  x   0.189 m

VB − VA =  56.7 V

Thus, the magnitude of the force is 1.32 x 10⁻⁵ N and direction of the electric force on the sphere towards the right.

The work done on the sphere by the electric force as it moves from A to B is 2.5 x 10⁻⁶ J.

The change of the electric potential energy as the sphere moves from A to B is 2.5 x 10⁻⁶ J.

The potential difference between A and B is 56.7 V.

Learn more about potential difference here: https://brainly.com/question/9060304

#SPJ1

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.