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what is the distance between (0,-8) and (3,2)

Sagot :

eunice1234

Answer: [tex]\Large\boxed{Distance=\sqrt{109}}[/tex]

Explanation:

Given information

(x₁, y₁) = (0, -8)

(x₂, y₂) = (3, 2)

Given the distance formula

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substitute values into the given formula

[tex]Distance=\sqrt{(3-0)^2+(2-(-8))^2}[/tex]

Simplify values in the parenthesis

[tex]Distance=\sqrt{(3)^2+(2+8)^2}[/tex]

[tex]Distance=\sqrt{(3)^2+(10)^2}[/tex]

Simplify the exponents

[tex]Distance=\sqrt{9+100[/tex]

Simplify by addition

[tex]\Large\boxed{Distance=\sqrt{109}}[/tex]

Hope this helps!! :)

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