Answered

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The sum of 10 consecutive integersstarting with 11, equals the sum of 5 consecutive integers, starting with
(A) 22
(B) 29
(C) 31
(D) 33

Sagot :

rdacoder

Answer: [tex]\large\boxed{29}[/tex]

Step-by-step explanation:

The sum of 10 consecutive integersstarting with 11

= 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 155

Lets try 29:

29 + 30 + 31 + 32 + 33 = 155

Therefore our answer is:

[tex]\large\boxed{29}[/tex]

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