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2CO(g) + O2(g) = 2CO2(g)
If 6.0 L of CO reacts at STP, how many liters of oxygen are required for the reaction?

2COg O2g 2CO2g If 60 L Of CO Reacts At STP How Many Liters Of Oxygen Are Required For The Reaction class=

Sagot :

CrystalQueen

Answer:

3.0 L O₂

Explanation:

If CO reacts at STP, it means that there are 1.0 moles of CO. To find the moles of O₂, you need to use the mole-to-mole ratio from the given equation.

1.0 moles CO            1 mole O₂
----------------------  x  ---------------------  =  0.5 moles O₂
                                2 moles CO

To calculate the liters of oxygen, you need to use Avogadro's Law:

V₁ / N₁ = V₂ / N₂

In this equation, "V₁" and "N₁" represent the volume and moles of the first molecule. "V₂" and "N₂" represent the volume and moles of the second molecule. You can plug the given and calculated values into the equation and simplify to isolate V₂.

V₁ = 6.0 L                     V₂ = ? L

N₁ = 1.0 moles              N₂ = 0.5 moles

V₁ / N₁ = V₂ / N₂                                            <----- Avogadro's Law

(6.0 L) / (1.0 moles) = V₂ / (0.5 moles)         <----- Insert values

6.0 = V₂ / (0.5 moles)                                   <----- Simplify left side

3.0 = V₂                                                         <----- Multiply both sides by 0.5

**I am not 100% confident on this answer. Please let me know if it is incorrect**

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