mwtoon
Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

8.0 liters I2 forms at STP. How many moles of KI were required for the reaction?

80 Liters I2 Forms At STP How Many Moles Of KI Were Required For The Reaction class=

Sagot :

CrystalQueen

Answer:

0.71 moles KI

Explanation:

At STP, there should be 1.0 moles at 22.4 L. However, there are only 8.0 L of I₂. Therefore, we must set up a proportion to find the correct moles of I₂.

[tex]\frac{1 mole}{22.4 L} =\frac{? moles}{8.0 L}[/tex]                                <----- Proportion

[tex]8.0 = 22.4(? moles)[/tex]                         <----- Cross multiply

[tex]0.36 = ? moles[/tex]                                 <----- Divide both sides by 22.4

To find the moles of KI, you can use the mole-to-mole ratio from the balanced equation coefficients. The final answer should have 2 sig figs.

2 KI(aq) + Cl₂(g) ---> 2KCl(aq) + 1 I₂(g)
^                                                   ^

0.36 moles I₂          2 moles KI
----------------------  x  --------------------  =  0.71 moles KI
                                   1 mole I₂

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.