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evaluate b-(-1/8)+c where b=2 and c=-7/4

Sagot :

eunice1234

Answer: [tex]\Large\boxed{\dfrac{3}{8} }[/tex]

Step-by-step explanation:

Given information

[tex]b=2[/tex]

[tex]c=-\dfrac{7}{4}[/tex]

Given expression

[tex]b-(-\dfrac{1}{8}) +c[/tex]

Substitute values into the expression

[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{7}{4} )[/tex]

Convert the fractions into the common denominator

Least Common Multiple (LCM) of 8 and 4 = 8

[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{7\times2}{4\times2} )[/tex]

[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{14}{8} )[/tex]

Simplify the parenthesis

[tex]=2+\dfrac{1}{8} -\dfrac{14}{8}[/tex]

Simplify by addition

[tex]=\dfrac{16}{8} +\dfrac{1}{8} -\dfrac{14}{8}[/tex]

[tex]=\dfrac{17}{8} -\dfrac{14}{8}[/tex]

Simplify by subtraction

[tex]\Large\boxed{=\dfrac{3}{8} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

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