Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of water at 25°C is 23.76 torr. (Assume ideal behavior.)

Sagot :

pstnonsonjoku

The vapor pressure is obtained as 23.47 torr.

What is the vapor pressure?

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

x2 = mole fraction of the  of the solute

Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:https://brainly.com/question/14718830

#SPJ1

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.