Taking into account the reaction stoichiometry and the definition of STP, 72.8 L of CO₂ gas is produced once the gas cools to STP.
Reaction stoichiometry
In first place, the balanced reaction is:
CaCO₃ → CaO + CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CaCO₃: 1 mole
- CaO: 1 mole
- CO₂: 1 mole
STP conditions
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Moles of CO₂ formed
The following rule of three can be applied: if by reaction stoichiometry 1 mole of CaCO₃ form 1 mole of CO₂, 3.25 moles of CaCO₃ form how many moles of CO₂?
[tex]moles of CO_{2} =\frac{3.25 moles of CaCO_{3}x 1 mole of CO_{2}}{1 moleof CaCO_{3}}[/tex]
moles of CO₂= 3.25 moles
Then, 3.25 moles of CO₂ are formed when 3.25 moles of CaCO₃ decomposes.
Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of CO₂ occupies a volume of 22.4 liters, 3.25 moles occupies how much volume?
[tex]volume= \frac{3.25 molesx22.4 L}{1 mole}[/tex]
volume= 72.8 L
Finally, 72.8 L of CO₂ gas is produced once the gas cools to STP.
Learn more about
the reaction stoichiometry:
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STP:
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