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What is the distance from (-3,8) and (13,-6)?

Sagot :

Answer:

d ≈ 21.26 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (- 3, 8 ) and (x₂, y₂ ) = (13 - 6 )

d = [tex]\sqrt{13-(-3))^2+(-6-8)^2}[/tex]

   = [tex]\sqrt{(13+3)^2+(-14)^2}[/tex]

   = [tex]\sqrt{16^2+196}[/tex]

   = [tex]\sqrt{256+196}[/tex]

   = [tex]\sqrt{452}[/tex]

   ≈ 21.26 units ( to 2 dec. places )

Answer:

The distance is 21.3

Step-by-step explanation:

The solution is in the attached image

View image zibahkeshiro