Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

can someone please help me with this

Topic= Surface area of prisms and cylinders

i keep getting the wrong answers

My working is incorrect please help me.

ANSWERS ARE FOR 4) 1234.10 AND 5)532.00​


Can Someone Please Help Me With ThisTopic Surface Area Of Prisms And Cylindersi Keep Getting The Wrong AnswersMy Working Is Incorrect Please Help MeANSWERS ARE class=

Sagot :

Step-by-step explanation:

4)

the surface area is

top and bottom : 2× pentagon (5 sides)

sides : 5× rectangle 14×8 ft²

let's start with the easiest : the rectangles.

5 × 14×8 = 560 ft²

the area of a pentagon is similar to any regular polygon :

n × triangle of side×height (to middle of pentagon) / 2

n = number of sides (5 in our case).

the middle or center of the pentagon is the top vertex of each triangle.

so,

5 × 14×9.63 / 2 = 5 × 7 × 9.63 = 337.05 ft²

and we have 2 of them (top and bottom), so

2×337.05 = 674.1 ft³

in total the surface area is

560 + 674.1 = 1,234.1 ft²

5)

6 sides :

top and bottom : 7×14 rectangle

left and right : 7×8 rectangle

front and back : 8×14 rectangle

so, we have

2× 7×14 = 196 mm²

2× 7×8 = 112 mm²

2× 8×14 = 224 mm²

in total that is : 532 mm²