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If an electron falls from the n = 2 to the n = 1 energy levels in a Hydrogen atom what wavelength of light is emitted?
Group of answer choices

A. 122 nm

B. 1024 nm

C. 97 nm

D. 103 nm

Sagot :

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The wavelength is obtained as 122 nm. Option A

What is the wavelength?

We know that from the Bohr model of the atom, an electron can move from a higher energy level to a lower energy level or from a lower energy level to a higher energy level. This is the idea of energy quantization as put forward by Neill Bohr.

The wavelength can be obtained by the use of the formula;

1/λ = RH(1/n^2initial - 1/n^2 final)

λ = wavelength of the emitted light

RH = Rydberg's constant

n intial = initial energy level

nfinal = final energy level

Thus;

1/λ = 1.09 * 10^7(1/1^2 - 1/2^2)

1/λ = 1.09 * 10^7( 1 - 0.25)

λ = 122 nm

Learn more about the wavelength:https://brainly.com/question/13533093

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