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If you do a lab that burns Magnesium in pure Oxygen what would the empirical formula of the compound be if you started with 0.6 g Magnesium and 0.4 g of Oxygen?
Group of answer choices

A. Mg2O2

B. Mg2O3

C. Mg3O2

D. MgO

Sagot :

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Answer:

Empirical Formula = MgO

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Explanation:

Elements = Mg O

Mass/ 0.6g/ 0.4g/

RAM 24 16

= 0.025 0.025

Divide by

the smallest = 0.025/ 0.025/

value. 0.025 0.025

Mole ratio = 1 : 1

Empirical Formula = MgO

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