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Sagot :
12x² + 102x² + 114x - 84
Answer:
Solution Given:
1st term: 6x²+39x-21
Taking common
3(2x²+13x-7)
doing middle term factorization
3(2x²+14x-x-7)
3(2x(x+7)-1(x+7))
3(x+7)(2x-1)
2nd term: 6x²+54x+84
taking common
6(x²+9x+14)
doing middle term factorization
6(x²+7x+2x+14)
6(x(x+7)+2(x+7))
2*3(x+7)(x+2)
Now
Least common multiple = 2*3(x+7)(2x-1)(x+2)
2(x+2)(6x²+39x-21)
(2x+4)(6x²+39x-21)
2x(6x²+39x-21)+4(6x² + 39x-21)
12x³+78x² - 42x+4(6x² + 39x-21)
12x³+78x² - 42x + 24x² + 156x-84
12x³ + 102x²-42x + 156x - 84
12x² + 102x² + 114x - 84
Answer:
[tex]12x^3+102x^2+114x-84[/tex]
Step-by-step explanation:
Given polynomials:
[tex]\begin{cases} 6x^2+39x-21\\6x^2+54x+84 \end{cases}[/tex]
Factor the polynomials:
Polynomial 1
[tex]\implies 6x^2+39x-21[/tex]
[tex]\implies 3(2x^2+13x-7)[/tex]
[tex]\implies 3(2x^2+14x-x-7)[/tex]
[tex]\implies 3[2x(x+7)-1(x+7)][/tex]
[tex]\implies 3(2x-1)(x+7)[/tex]
Polynomial 2
[tex]\implies 6x^2+54x+84[/tex]
[tex]\implies 6(x^2+9x+14)[/tex]
[tex]\implies 6(x^2+7x+2x+14)[/tex]
[tex]\implies 6[x(x+7)+2(x+7)][/tex]
[tex]\implies 6(x+2)(x+7)[/tex]
[tex]\implies 2 \cdot 3(x+2)(x+7)[/tex]
The lowest common multiplier (LCM) of two polynomials a and b is the smallest multiplier that is divisible by both a and b.
Therefore, the LCM of the two polynomials is:
[tex]\implies 2 \cdot 3(x+7)(x+2)(2x-1)[/tex]
[tex]\implies (6x^2+54x+84)(2x-1)[/tex]
[tex]\implies 12x^3+108x^2+168x-6x^2-54x-84[/tex]
[tex]\implies 12x^3+102x^2+114x-84[/tex]
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