Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

If the temperature of a gas is increased from 20°C to 35°C, what is the new pressure if the original pressure was 1.2 atm? Assume that volume is constant.

A. 0.6 atm

B. 1.3 atm

C. 1.0 atm

D. 2.6 atm


Sagot :

The new pressure of the gas would be = 2.1 atm.

Calculation of gas pressure

The initial temperature of the gas(T1) = 20°C

The final temperature of the gas(T2)= 35°C

The volume= constant

The Original pressure (P1) = 1.2atm

The new pressure (P2) =?

Using the gas law P1/T1 = P2/T2

Make P2 the subject of formula;

P2= P1×T2/T1

P2= 1.2 × 35/20

P2= 42/20

P2= 2.1 atm

Therefore, the new pressure of the gas would be = 2.1 atm.

Learn more about pressure here:

https://brainly.com/question/25965960

#SPJ1

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.