Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

△ABC has vertices A(-2, 0), B(0,8), and C(4,2). Find the coordinates of the point of congruency of the altitudes (H)

Sagot :

Lanuel

Based on the calculations, the coordinates of the point of congruency of the altitudes (H) are (-160/11, 40/11).

What is a triangle?

A triangle can be defined as a two-dimensional geometric shape that comprises three (3) sides, three (3) vertices and three (3) angles only.

What is a slope?

A slope is also referred to as gradient and it's typically used to describe both the ratio, direction and steepness of the function of a straight line.

How to determine a slope?

Mathematically, the slope of a straight line can be calculated by using this formula;

[tex]Slope, m = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope, m = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]

Assuming the following parameters for triangle ABC:

  • Let AM be the altitudes on BC.
  • Let BN be the altitudes on CA.
  • Let CL be the altitudes on AB.

For the slope of BC, we have:

Slope of BC = (2 - 8)/(4 - 0)

Slope of BC = -6/4

Slope of BC = -3/2.

For the slope of CA, we have:

Slope of CA = (2 - 0)/(4 - (-2))

Slope of CA = 2/6

Slope of CA = 1/3.

For the slope of AB, we have:

Slope of AB = (8 - 0)/(0 - (-2))

Slope of AB = 8/2

Slope of AB = 4.

Note: The point of concurrency of three altitudes in a triangle is referred to as orthocenter.

Since side AB is perpendicular to side QC, we have:

m₁ × m₂ = -1

Slope of AB × Slope of QC = -1

Slope of QC = (k - 4)/(h - 2)

4 × (k - 4)/(h - 2) = -1

(4k - 16)/(h - 2) = -1

4k - 16 = -h + 2

4k + h = 18    .......equation 1.

Similarly, we have the following:

Slope of BC × Slope of AH = -1

-3/2 × (k)/(h + 2) = -1

3k/(2h + 4) = 1

3k = 2h + 4

3k - 2h = 4     .......equation 2.

Solving eqn. 1 and eqn. 2 simultaneously, we have:

8k + 2h = 36

3k - 2h = 4

11k = 40

k = 40/11.

For the value of h, we have:

h = -4k

h = -4 × (40/11)

h = -160/11

Therefore, the coordinates of the point of congruency of the altitudes (H) are (-160/11, 40/11).

Read more on point of congruency here: https://brainly.com/question/14375863

#SPJ1