Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Values of c and d make the equation true are c=6, d=2
Equations
- We must find the values of c and d that make the below equation be true
[tex]\sqrt[3]{162x^{c}y^{5} } = 3x^{2} y^{3} \sqrt[3]{6y^{d} }[/tex]
- cubing on both sides -
[tex](\sqrt[3]{162x^{c}y^{5} })^{3} = (3x^{2} y^{3} \sqrt[3]{6y^{d} })^{3}[/tex]
- The left side just simplifies the cubic root with the cube:
[tex]{162x^{c}y^{5} } = (3x^{2} y^{3} \sqrt[3]{6y^{d} })^{3}[/tex]
- On the right side, we'll simplify the cubic root where possible and power what's outside of the root:
[tex]{162x^{c}y^{5} } = 27x^{6} y^{3} ({6y^{d})[/tex]
- Simplifying
[tex]{x^{c}y^{5} } = x^{6} y^{3} ({y^{d})[/tex]
[tex]{x^{c}y^{5} } = x^{6} y^{3+d}[/tex]
- On equating,
c = 6
d = 2
To learn more about equations from the given link
https://brainly.com/question/14751707
#SPJ4
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
