Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The two stadiums are 2,871 meters
A blimp = point A
stadium 1 = point B
stadium 2 = point C
height of the blimp , AD = 1600
depression angle of stadium 1 , ∠y = 71.7°
depression angle of stadium 2 , ∠x = 25.2°
distance between the two stadiums = d
So, it forms 2 triangles ABD and ACD,
Using the trigonometric ratios,
tan θ = Altitude / Base
DC = AD × tan (90° - x)
= 1600 × tan( 90° - 25.2° )
= 1600 × cot(25.2°)
= 1600 × 2.13
DB = AD × tan (90° - y)
= 1600 × tan( 90° - 71.7° )
= 1600 × cot(71.7°)
= 1600 × 0.33
∴ d = DC - DB
= 1600 * [ tan( 90° - 25.2° ) - tan( 90° - 71.7° ) ]
= 2,871 meters
To learn more about angle of depression from the given link
https://brainly.com/question/9723082
#SPJ4
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
