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Sagot :
The domain of f(x) is all set of real values while, the domain of g(x) is x ≤ -1 or x ≥ 2 and both functions have the same range
Part A: Compare the domain and range of the function f(x) to g(x)
The functions are given as:
f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4
g(x) = √(x^2 - x - 2)
Domain
The polynomial function f(x) has no restriction on its input.
So, the domain of f(x) is all set of real values
Set the radical of g(x) = √(x^2 - x - 2) greater than 0
x^2 - x - 2 ≥ 0
Factorize
(x + 1)(x - 2) ≥ 0
Solve for x
x ≥ -1 and x ≥ 2
Combine both inequalities
x ≤ -1 and x ≥ 2
So, the domain of g(x) is x ≤ -1 or x ≥ 2
Range
Using a graphical calculator, we have:
- Range of f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4 ⇒ f(x) ≥ 0
- Range of g(x) = √(x^2 - x - 2) ⇒ g(x) ≥ 0
Hence, both functions have the same range
How do the breaks in the domain of h(x) relate to the zeros of f(x)?
We have:
h(x) = (-x^2 + x)/(x^2 - x - 2)
Set the denominator to 0
x^2 - x - 2 = 0
The above represents the radical of the function f(x)
This means that the breaks in the domain of h(x) and the zeros of f(x) are the same
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Complete question
Let f(x) = x^4 - 2x^3 - 3x^2 + 4x + 4, g(x) = √(x^2 - x - 2) and h(x) = (-x^2 + x)/(x^2 - x - 2)
Part A: Use complete sentences to compare the domain and range of the polynomial function f (x) to that of the radical function g(x). (5 points)
Part B: How do the breaks in the domain of h (x) relate to the zeros of f (x)? (5 points)
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