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Sagot :
The molarity of an aqueous solution of isopropanol = 15.09 mol/L
Molality = 12.79 m
This gives that 12.79 moles of isopropanol is dissolved in 1000 grams of water.
Density = 1.180 g/mL
We know that,
Density= mass/volume
volume = mass/density
= 1000/1.180
Volume = 847.46 ml
Molarity can be defined as the mass of solute per liter of the solution.
Molarity = moles × 1000/volume ------> (1)
The moles of isopropanol in 847.46 ml solution is 12.79.
On substituting in (1)
Molarity = 12.79 × 1000/847.46
Molarity= 15.09 mol/L
The molarity of aqueous solution of isopropanol is 15.09 mol/L
What is molality?
The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.
What is molarity?
- The amount of a substance in a specific volume of solution is known as its molarity (M).
- The number of moles of a solute per liter of a solution is known as molarity.
- The molar concentration of a solution is another name for molarity.
To learn more about molality visit:
https://brainly.com/question/17075687
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