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How many protons, neutrons and electrons, in that order are present in the anion formed by one atom of 79se? group of answer choices 34, 34, 45 34, 45, 34 32, 45, 34 34, 45, 36 36, 45, 36

Sagot :

There are  34  protons , 45 neutrons and 36 electrons, in that order are present in the anion formed by one atom of 79Se .

Calculation

The number of electron / protons ( present in the nucleus ) of the atom is equal to atomic number .

The sum of  number of electron / protons ( present in the nucleus ) and neutrons  ( present in the nucleus )  of the atom is called atomic mass.

The atomic number of Se = 34

The Mass number or atomic mass of Se = 79

The anion of Se = [tex]Se^{-2}[/tex]

It means two electron loss by Se and form  [tex]Se^{-2}[/tex] .

So , the difference between number of electrons and protons = 2

Hence , number of electron and proton in  [tex]Se^{-2}[/tex] anion is 34 ( two less than number of protons ) and 36

To learn more about neutrons  please click here .

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