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Assume earth is approximately a uniform, solid sphere that has a mass of 5.98×1024 kg and a radius of 6.38×106 m. calculate the angular momentum ????z of earth as it spins on its central axis once each day.

Sagot :

The angular momentum of earth is

7×10^33 kgm^2/sec

Given:

mass of earth = 5.98×1024 kg

radius of earth = 6.38×10^6 m

To Find:

angular momentum

Solution:

For earth we have moment of inertia as

I = 2/5mR^2

and angular velocity as ω = 2π/T

Thus angular momentum is given as

L= 2/5mR^2*2π/T

L = 2/5*5.98×10^24*(6.38×10^6)^2*2*3.14/86400s

L = 7 × 10^33 kg/m^2/sec

So, angular momentum of earth is

So, angular momentum of earth is 7×10^33 kgm^2/sec

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