Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of so that the following is true.
P(-0.78≤Z≤c)=0.7657

Sagot :

For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166

How to find the p-value from 2 z-scores?

We want to find the p-value between 2 z-scores expressed as;

P(-0.78 < z < c) = 0.7657

To solve this, we will solve it as;

0/7657= 1 - [P(z < -0.78)  + P(z > c)]

From normal distribution table, we have that;

P(z < -0.78) =  0.217695

Thus;

0.7657 = 1 - (0.217695 + c)

c = 1 - 0.7657 - 0.217695

c = 0.0166

Thus, For a standard normal distribution, the value of the z-score represented as c in P(-0.78≤Z≤c)=0.7657 is 0.0166

Read more about p-value from z-score at; brainly.com/question/4621112

#SPJ1

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.