Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Find the equation of the circle whose center and radius are given.

center ( 5, 6), radius = 3


Sagot :

The  equation of the circle whose center and radius are given as center ( 5, 6), radius = 3 is; x² + y² - 10x - 12y + 52 = 0

How to find the equation of a circle?

We know that the general form of equation of a circle whose center is (h, k) and radius is r is expressed as;

(x - h)² + (y - k)² = r²     --- (1)

We are given;

Center coordinate; (h, k) = (5, 6)

radius; r = 3

Plug in the values of h = 5 , k = 6 and r = 3 into the equation to get;

(x - 5)² + (y - 6)² = 3²

Expanding the equation gives;

x² - 10x + 25 + y² - 12y + 36 = 9

x² + y2 - 10x - 12y + 52 = 0

Thus the  equation of the circle whose center and radius are given as center ( 5, 6), radius = 3 is; x² + y² - 10x - 12y + 52 = 0

Read more about Equation of a Circle at; https://brainly.com/question/1559324

#SPJ1

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.