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Sagot :
The equation of the circle whose center and radius are given as center ( 5, 6), radius = 3 is; x² + y² - 10x - 12y + 52 = 0
How to find the equation of a circle?
We know that the general form of equation of a circle whose center is (h, k) and radius is r is expressed as;
(x - h)² + (y - k)² = r² --- (1)
We are given;
Center coordinate; (h, k) = (5, 6)
radius; r = 3
Plug in the values of h = 5 , k = 6 and r = 3 into the equation to get;
(x - 5)² + (y - 6)² = 3²
Expanding the equation gives;
x² - 10x + 25 + y² - 12y + 36 = 9
x² + y2 - 10x - 12y + 52 = 0
Thus the equation of the circle whose center and radius are given as center ( 5, 6), radius = 3 is; x² + y² - 10x - 12y + 52 = 0
Read more about Equation of a Circle at; https://brainly.com/question/1559324
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