At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The dart player throws a dart horizontally at a speed of 24.75 m/s.
In this question,
The horizontal distance traveled by the dart, x = 2.5 m
The dart hits the board 5 cm below the height from which it was thrown.
⇒ 5 cm = 0.05 m
Let the time taken by the dart to hit the board is t.
The time taken can be calculated using the Newton's second law of motion,
[tex]y = ut+\frac{1}{2}at^{2}[/tex]
Put, u = 0, a = -g and g = 9.8
On substituting the above values, we get
⇒ [tex]-0.05 = 0-\frac{1}{2}(9.8)t^{2}[/tex]
⇒ [tex]0.05(\frac{2}{9.8}) = t^{2}[/tex]
⇒ [tex]t^{2} =0.0102[/tex]
⇒ [tex]t=\sqrt{0.0102}[/tex]
⇒ t = 0.1010 s
Now, the velocity (speed) can be calculated as
displacement = speed × time
⇒ 2.5 = speed × 0.1010
⇒ speed = [tex]\frac{2.5}{0.1010}[/tex]
⇒ speed = 24.7524 m/s
Hence we can conclude that the dart player throws a dart horizontally at a speed of 24.75 m/s.
Learn more about dart and Newton's second law of motion here
https://brainly.com/question/19957013
#SPJ4
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
