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Cube a and cube b are similar solids. the volume of cube a is 27 cubic inches, and the volume of cube b is 125 cubic inches. how many times larger is the base area of cube b than the base area of cube a?

Sagot :

The base area of cube B is 25/9  times larger than the base area of cube A.

What is area cubic?

  • Surface area of cube is the sum of areas of all the faces of cube, that covers it.
  • The formula for surface area is equal to six times of square of length of the sides of cube.
  • It is represented by 6a2, where a is the side length of cube. It is basically the total surface area.

We know that volume of cube with each side of  units is equal to .

First of all, we will find the each side of cube A and B as:

[tex]A^{3} = 27[/tex]

[tex]\sqrt[3]{A^{3} } = \sqrt[3]{27}[/tex]

A = 3

[tex]B^{3} = 125[/tex]

[tex]\sqrt[3]{B^{3} } = \sqrt[3]{125}[/tex]

B = 5

Now, we will find base area of both cubes as:

[tex]\frac{Base area of B}{Base area of A} = \frac{B^{2} }{A^{2} }[/tex]

[tex]\frac{Base area of B}{Base area of A} = \frac{5^{2} }{3^{2} }[/tex]

[tex]\frac{Base area of B}{Base area of A} = \frac{25}{9}[/tex]

Therefore, the base area of cube B is 25/9  times larger than the base area of cube A.

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